Reverse integer
https://www.interviewbit.com/old/problems/reverse-integer/
int Solution::reverse(int n) {
long long res=0;
while(n){
res=res*10+n%10;
if(res>INT_MAX||res<INT_MIN) return 0;
n=n/10;
}
return res;
}
Perfect Peak of Array
Given an integer array A of size N . You need to check that whether there exist a element which is strictly greater than all the elements on left of it and strictly smaller than all the elements on right of it. If it exists return 1 else return 0 . https://www.interviewbit.com/old/problems/perfect-peak-of-array/ int Solution::perfectPeak(vector<int> &A) { int ans=-1; int l[A.size()]; int r[A.size()]; l[0]=A[0]; r[A.size()-1]=A[A.size()-1]; for(int i=1;i<A.size();i++){ l[i] = max(A[i],l[i-1]); } for(int i=A.size()-2;i>=0;i--){ r[i] = min(A[i],r[i+1]); } for(int i=1;i<A.size()-1;i++){ if(A[i]>l[i-1]&&A[i]<r[i+1]){ return 1; } } if(ans==-1){ return 0; } }
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